| \[[AB]\,\,mol\,\,d{{m}^{-3}}\] | Rate of decomposition of\[AB\]in\[mol\,\,d{{m}^{-3}}\,\,{{s}^{-1}}\] |
| 0.20 | \[2.75\times {{10}^{-8}}\] |
| 0.40 | \[11.0\times {{10}^{-8}}\] |
| 0.60 | \[24.75\times {{10}^{-8}}\] |
A) 1.5
B) 0
C) 1
D) 2
Correct Answer: D
Solution :
\[AB\xrightarrow{{}}\]Product Rate\[=k{{[AB]}^{n}}\] \[{{(Rate)}_{1}}=k{{[0.20]}^{n}}=2.75\times {{10}^{-8}}\] ... (i) \[{{(Rate)}_{2}}=k{{[0.40]}^{n}}=11.0\times {{10}^{-8}}\] ... (ii) Dividing Eq. (ii) by Eq. (i), \[\frac{{{(Rate)}_{2}}}{{{(Rate)}_{1}}}=\frac{k{{[0.40]}^{n}}}{k{{[0.20]}^{n}}}=\frac{11.0\times {{10}^{-8}}}{2.75\times {{10}^{-8}}}\] \[{{2}^{n}}=4\] or \[{{2}^{n}}={{2}^{2}}\] Hence, \[n=2\]
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