Manipal Engineering Manipal Engineering Solved Paper-2009

  • question_answer
     Youngs   double   slit   experiment   gives interface fringes of width 0.3 mm. A thin glass plate made of material of refractive index 1.5 is kept in the path of light from one of the slits, then the fringe width becomes

    A)  zero                                     

    B)  0.3 mm

    C)  0.45 mm             

    D)         0.15 mm

    Correct Answer: B

    Solution :

                    When a this glass plate of thickness\[t\]and refractive index\[\mu \], is introduced in one of the paths of the interfering waves then the path increases by\[(\mu -1)t\]and the whole pattern shifts by                 \[{{y}_{0}}=\frac{D}{d}(\mu -1)t\] Shifting is towards the side in which the plate is introduced without any change in fringe width. Therefore, when a glass plate of refractive index 1.5 is kept in the path of light from one of the slits, only the fringes get shifted but the fringe width remains unchanged.


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