A) \[\frac{13}{2}\]
B) 13
C) 26
D) 52
Correct Answer: A
Solution :
Given equation of sphere is \[{{x}^{2}}+{{y}^{2}}+{{z}^{2}}-12x-4y-3z=0\] \[\therefore \]Centre of sphere is\[\left( 6,\,\,2,\,\,\frac{3}{2} \right)\]. \[\therefore \]Radius of sphere\[=\sqrt{{{(6)}^{2}}+{{(2)}^{2}}+{{\left( \frac{3}{2} \right)}^{2}}}\] \[=\sqrt{36+4+\frac{9}{4}}=\sqrt{\frac{169}{4}}\] \[=\frac{13}{2}\]
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