Manipal Engineering Manipal Engineering Solved Paper-2009

  • question_answer
    \[{{\sinh }^{-1}}2+{{\sinh }^{-1}}3=x\Rightarrow \cosh x\]is equal to

    A) \[\frac{1}{2}(3\sqrt{5}+2\sqrt{10})\]      

    B) \[\frac{1}{2}(3\sqrt{5}-2\sqrt{10})\]

    C) \[\frac{1}{2}(12+2\sqrt{50})\]

    D)        \[\frac{1}{2}(12-2\sqrt{50})\]

    Correct Answer: C

    Solution :

    Given,\[{{\sinh }^{-1}}2+{{\sinh }^{-1}}3=x\] \[\Rightarrow \]               \[\cosh ({{\sinh }^{-1}}2+{{\sinh }^{-1}}3)=\cosh x\] \[\Rightarrow \]               \[\cosh ({{\sinh }^{-1}}2)\cosh ({{\sinh }^{-1}}3)\]                                 \[+\sinh ({{\sinh }^{-1}}2)\sinh ({{\sinh }^{-1}}3)\]                 \[=\cosh x\] \[\Rightarrow \]               \[\cosh x=\cosh ({{\cosh }^{-1}}\sqrt{1+{{2}^{2}}})\]                 \[\times \cosh ({{\cosh }^{-1}}\sqrt{1+{{3}^{2}}})+2\times 3\] \[\Rightarrow \]               \[\cosh x=(\sqrt{5},\,\,\sqrt{10}+6)\times \frac{2}{2}\]                 \[=\frac{1}{2}(12+2\sqrt{50})\]


You need to login to perform this action.
You will be redirected in 3 sec spinner