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Manipal Engineering Manipal Engineering Solved Paper-2009

  • question_answer
    The rms velocity of molecules of a gas of density\[4\,\,kg\,\,{{m}^{-3}}\]and pressure\[1.2\times {{10}^{5}}\,\,N{{m}^{-2}}\]is

    A) \[300\,\,m{{s}^{-1}}\]                   

    B) \[900\,\,m{{s}^{-1}}\]

    C) \[120\,\,m{{s}^{-1}}\]   

    D)        \[600\,\,m{{s}^{-1}}\]

    Correct Answer: A

    Solution :

            \[{{v}_{rms}}=\sqrt{\frac{3p}{d}}\]                 \[=\sqrt{\frac{3\times 1.2\times {{10}^{5}}}{4}}=300\,\,m{{s}^{-1}}\]


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