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Manipal Engineering Manipal Engineering Solved Paper-2009

  • question_answer
    A bivalent metal has an equivalent mass of 32. The molecular mass of the metal nitrate is

    A)  182                                       

    B)  168

    C)  192                       

    D)         188

    Correct Answer: D

    Solution :

    Atomic mass of the metal\[=32\times 2=64\] Formula of metal nitrate\[=M{{(N{{O}_{3}})}_{2}}\] \[\therefore \]Molecular mass\[=64+28+96=188\]


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