A) \[10\,\,N\]
B) \[1\,\,N\]
C) \[2\,\,N\]
D) \[0.1\,\,N\]
Correct Answer: B
Solution :
Molecular weight of\[{{(COOH)}_{2}}\cdot 2{{H}_{2}}O=126\,\,g\] \[\therefore \]Equivalent weight\[=\frac{126}{2}=63\] \[[\because basicity=2]\] Weight of\[{{(COOH)}_{2}}\cdot 2{{H}_{2}}O\]in solution \[=32.5\,\,g\] \[\text{Normality=}\frac{\text{number}\,\,\text{of}\,\,\text{gram}\,\,\text{equivalent}}{\text{volume}\,\,\text{(in}\,\,\text{litre)}}\] \[=\frac{32.5/63}{0.5}\] \[=1\,\,N\]
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