Manipal Engineering Manipal Engineering Solved Paper-2008

  • question_answer
    The concentration of a reactant X decreases from\[0.1M\]to\[0.005M\]in 40 min. If the reaction follows first order kinetics, the rate of the reaction when the concentration of\[X\]is \[0.01\,\,M\]will be

    A) \[1.73\times {{10}^{-4}}M\,\,{{\min }^{-1}}\]

    B) \[3.47\times {{10}^{-4}}M\,\,{{\min }^{-1}}\]

    C) \[3.47\times {{10}^{-5}}M\,\,{{\min }^{-1}}\]

    D) \[7.5\times {{10}^{-4}}M\,\,{{\min }^{-1}}\]

    Correct Answer: D

    Solution :

                    \[k=\frac{2.303}{t}\log \frac{{{A}_{0}}}{A}\]                    \[=\frac{2.303}{40}\log \frac{0.1}{0.005}\]                    \[=\frac{2.303}{40}\log 20=0.075\] Rate of reaction when concentration of\[X\]is\[0.01\,\,M\]will be                 \[0.075\times 0.01=7.5\times {{10}^{-4}}M\,\,{{\min }^{-1}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner