Manipal Engineering Manipal Engineering Solved Paper-2008

  • question_answer
    A diode having potential difference 0.5 V across its junction which does not depend on current, is connected in series with resistance of 20 \[\Omega \] across source. If 0.1 A current passes through resistance then what is the voltage of the source?

    A)  1.5V                                     

    B)  2.0V

    C)  2.5 V                    

    D)         5 V

    Correct Answer: C

    Solution :

    The circuit diagram of the given situation is shown. Since, it is a closed mesh, the voltage is \[V=V+IR\] Given,   \[V=0.5\]volt,\[I=0.1\,\,A\],\[R=20\Omega \] \[\therefore \]  \[V=0.5+0.1\times 20\]                 \[V=2.5\]volt


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