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Manipal Engineering Manipal Engineering Solved Paper-2008

  • question_answer
    A body of mass 2 kg moving with a velocity of 3 m/s collides head on with a body of mass 1 kg moving in opposite direction with a velocity of 4 m/s. After collision two bodies stick together and move with a common velocity which in m/s is equal to

    A)  1/4                                       

    B)  1/3

    C)  2/3                       

    D)         3/4

    Correct Answer: C

    Solution :

    \[{{m}_{1}}{{v}_{1}}-{{m}_{2}}{{v}_{2}}=({{m}_{1}}+{{m}_{2}})v\] \[\Rightarrow \,\,2\times 3-1\times 4=(2+1)v\] \[\Rightarrow \]                      \[v=\frac{2}{3}m/s\]


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