A) 4 cm
B) 2 cm
C) 1 cm
D) None of these
Correct Answer: B
Solution :
If object in a denser medium is seen from a rarer medium then image of object will appear at a lesser distance. The distance between object and its image, called as normal shift is given by \[x=t\left[ 1-\frac{1}{\mu } \right]\] Here, \[t=6\,\,cm\] \[\mu =1.5\] \[\therefore \] \[x=6\left[ 1-\frac{1}{1.5} \right]\] \[=6\left[ \frac{0.5}{1.5} \right]\] \[=2\,\,cm\]
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