A) \[21x+77y-101=0\]
B) \[99x-27y+81=0\]
C) \[21x-77y+101=0\]
D) None of the above
Correct Answer: A
Solution :
Given equations of lines are\[3x-4y+7=0\]and\[-12x-5y+2=0\] \[{{a}_{1}}{{a}_{2}}+{{b}_{1}}{{b}_{2}}=3\times (-12)+(-4)(-5)\] \[=-36+20=-16\] \[\Rightarrow \] \[{{a}_{1}}{{a}_{2}}+{{b}_{1}}{{b}_{2}}\le 0\] \[\therefore \]Obtuse angle bisector is \[\frac{3x-4y+7}{\sqrt{{{3}^{2}}+{{(-4)}^{2}}}}=-\frac{-12x-5y+2}{\sqrt{{{(-12)}^{2}}+{{(-5)}^{2}}}}\] \[\Rightarrow \] \[13(3x-4y+7)=-5(-12x-5y+2)\] \[\Rightarrow \] \[21x+77y-101=0\]
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