A) phenyl hydrazine
B) hydroxyl amine
C) Fehling solution
D) sodium bisulphite
Correct Answer: C
Solution :
Fehling solution is only reduced by aldehydes but not by ketones, therefore it is used to distinguish between aldehyde\[({{C}_{2}}{{H}_{5}}CHO)\]and ketone\[{{(C{{H}_{3}})}_{2}}CO\]. \[{{C}_{2}}{{H}_{5}}CHO+\underset{Fehling\,\,solution}{\mathop{Cu{{(OH)}_{2}}}}\,\xrightarrow{{}}{{C}_{2}}{{H}_{5}}COOH\] \[+\underset{red\,\,ppt.}{\mathop{C{{u}_{2}}O}}\,+{{H}_{2}}O\] \[{{(C{{H}_{3}})}_{2}}C=O+\underset{Fehling\,\,solutions}{\mathop{Cu(O{{H}_{2}})}}\,\xrightarrow{{}}\]No reaction
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