A) \[{{(C{{H}_{3}}CO)}_{2}}N-C-{{(C{{H}_{3}})}_{3}}\]
B) \[{{(C{{H}_{3}})}_{2}}CH-\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{N}}\,-COC{{H}_{3}}\]
C) \[{{(C{{H}_{3}})}_{2}}CHN{{(CO{{H}_{3}})}_{2}}\]
D) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}-\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{N}}\,-COC{{H}_{3}}\]
Correct Answer: C
Solution :
\[{{(C{{H}_{3}})}_{2}}CH\cdot N{{H}_{2}}+2C{{H}_{3}}COCl\xrightarrow[-HCl]{}\] \[iso.\text{propyl}\,\,\text{amine}\] \[(pri\,\,\text{amine)}\] \[{{(C{{H}_{3}})}_{2}}CH-N{{(COC{{H}_{3}})}_{2}}\]
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