A) Calcium
B) Chromium
C) Iron
D) Cobalt
Correct Answer: B
Solution :
The electronic configuration of\[_{24}Cr\]is\[={{[Ar]}_{18}}3{{d}^{5}},\,\,4{{s}^{1}}\] Chromium after loss of one electron gain stable configuration due to presence of half-filled d orbitals, therefore its second ionization enthalpy is highest.
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