A) 24 g
B) 36 g
C) 60 g
D) 72 g
Correct Answer: D
Solution :
\[\Delta {{T}_{f}}=\frac{{{k}_{f}}\times 1000\times w}{M\times W}\] \[w=\frac{\Delta {{T}_{f}}\times M\times W}{{{k}_{f}}\times 1000}\] \[\Delta {{T}_{f}}=0-(-0.6)={{0.6}^{o}}C\] \[M=60\,\,g/mol\] \[{{k}_{f}}={{1.5}^{o}}C\,\,kg\,\,mo{{l}^{-1}}\] \[W=3\times {{10}^{3}}g\] \[w=\frac{0.6\times 60\times 3\times {{10}^{3}}}{1.5\times 1000}\] \[=72\,\,g\]
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