A) Its bond order is one and it is paramagnetic
B) Its bond order is two and it is diamagnetic
C) Its bond order is one and it is diamagnetic
D) Its bond order is two and it is paramagnetic
Correct Answer: C
Solution :
The electronic configuration of peroxide ion\[(O_{2}^{2-})\]is as: \[O_{2}^{2-}:KK{{(\sigma 2s)}^{2}}{{(\overset{*}{\mathop{\sigma }}\,2s)}^{2}}{{(\sigma 2{{p}_{z}})}^{2}}{{(\pi 2{{p}_{x}})}^{2}}\] \[{{(\pi 2{{p}_{y}})}^{2}}{{({{\pi }^{*}}2{{p}_{x}})}^{2}}{{({{\pi }^{*}}2{{p}_{y}})}^{2}}\] Bond order\[=\frac{8-6}{2}=1\] Since, all the electrons in moledular orbitals are paired, it is diamagnetic.
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