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Manipal Engineering Manipal Engineering Solved Paper-2008

  • question_answer
    A laser beam of pulse power \[{{10}^{12}}\]W is focused on an object of area\[{{10}^{-4}}c{{m}^{2}}\]. The energy flux in watt/\[c{{m}^{2}}\] at the point of focus is

    A)  \[{{10}^{20}}\]

    B)                                         \[{{10}^{16}}\]

    C) \[{{10}^{8}}\]                    

    D)        \[{{10}^{4}}\]

    Correct Answer: B

    Solution :

    Electric flux \[\phi =\frac{pulse\,\,power}{area}=\frac{{{10}^{12}}}{{{10}^{-4}}}={{10}^{16}}\,\,W/c{{m}^{2}}\]


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