Manipal Engineering Manipal Engineering Solved Paper-2008

  • question_answer
    A cane is taken out from a refrigerator at \[0{}^\circ C\]. The atmospheric temperature is \[25{}^\circ C\]. If \[{{t}_{1}}\] is the time taken to heat from \[0{}^\circ C\] to \[5{}^\circ C\] and \[{{t}_{2}}\] is the time taken from \[10{}^\circ C\] to \[15{}^\circ C\], then

    A)  \[{{t}_{1}}>{{t}_{2}}\]                                   

    B)  \[{{t}_{1}}<{{t}_{2}}\]

    C)  \[{{t}_{1}}={{t}_{2}}\]                   

    D)         there is no relation

    Correct Answer: B

    Solution :

    According to Newtons law of cooling\[{{t}_{1}}\]will be less than\[{{t}_{2}}\].


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