A) \[{{10}^{2}}Bq\]
B) \[3\times {{10}^{10}}Bq\]
C) \[4.17\times {{10}^{24}}Bq\]
D) \[1.16\times {{10}^{5}}Bq\]
Correct Answer: C
Solution :
\[T=100\mu s={{10}^{-4}}s\] \[\lambda =\frac{0.6931}{T}=\frac{0.6931}{{{10}^{-4}}}\] \[=0.6931\times {{10}^{-4}}\,\,{{s}^{-1}}\] Number of atoms in 215 mg \[=\frac{6.023\times {{10}^{23}}}{215}\times 215\times {{10}^{-3}}\] \[\therefore \] \[N=6.023\times {{10}^{20}}\] Activity, \[\frac{dN}{dt}=\lambda N\] \[=0.6931\times {{10}^{4}}\times 6.023\times {{10}^{20}}\] \[=4.17\times {{10}^{24}}Bq\]
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