A) \[1200\,m/{{s}^{2}}\]
B) \[1000\,m/{{s}^{2}}\]
C) \[2000\,m/{{s}^{2}}\]
D) \[1500\,m/{{s}^{2}}\]
Correct Answer: D
Solution :
According to Newtons second law of motion, force acting on a body is equal to the rate of change of momentum during impact. \[F=\frac{\Delta p}{\Delta t}\] Also, \[F=ma\] \[\therefore \] \[ma=\frac{{{p}_{2}}-{{p}_{1}}}{\Delta t}\] or \[a=\frac{m{{v}_{2}}-(-m{{v}_{1}})}{m\,\,\Delta t}\] or \[a=\frac{{{v}_{2}}+{{v}_{1}}}{\Delta t}\] \[\therefore \] \[a=\frac{\sqrt{2\times 10\times 20}+\sqrt{2\times 10\times 5}}{0.02}\] or \[a=\frac{20+10}{0.02}=1500\,\,m/{{s}^{2}}\]
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