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Manipal Engineering Manipal Engineering Solved Paper-2008

  • question_answer
    Water is moving with a speed of 5.18 \[m{{s}^{-1}}\] through a pipe with a cross-sectional area of 4.20\[c{{m}^{2}}\]. The water gradually descends 9.66 m as the pipe increase in area to 7.60\[c{{m}^{2}}\]. The speed of flow at the lower level is

    A)  3.0\[m{{s}^{-1}}\]          

    B)         5.7\[m{{s}^{-1}}\]

    C)  3.82\[m{{s}^{-1}}\]        

    D)         2.86\[m{{s}^{-1}}\]

    Correct Answer: D

    Solution :

    \[{{a}_{1}}{{v}_{1}}={{a}_{2}}{{v}_{2}}\] \[\Rightarrow \]               \[4.20\times 5.18=7.60\times {{v}_{2}}\] \[\Rightarrow \]               \[{{v}_{2}}=2.86\,\,m/s\]


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