JEE Main & Advanced Physics Two Dimensional Motion JEE PYQ - Two Dimensional Relative Motion

  • question_answer
    A passenger train of length 60 m travels at a speed of 80 km/hr. Another freight train of length 120 m travels at a speed of 30 km/hr, The ratio of times taken by the passenger train to completely cross the freight train when: (i) they are moving in the same direction, and (ii) in the opposite direction is- [JEE Main 12-Jan-2019 Morning]

    A) (a)\[\frac{25}{11}\]

    B) (b)\[\frac{3}{2}\]

    C) (c)\[\frac{5}{2}\]

    D) (d)\[\frac{11}{5}\]

    Correct Answer: D

    Solution :

    [d] The total distance to be travelled by the train is 60+120=180 m.
    When the trains are moving in the same direction, relative velocity is \[{{v}_{1}}-{{v}_{2}}=80-30=50km\,h{{r}^{-1}}\]so time taken to cross each other.
    \[{{t}_{1}}=\frac{180}{50\times \frac{{{10}^{3}}}{3600}}=\frac{18\times 18}{25}s\]
    When the trains are moving in opposite direction relative velocity,
    \[|{{v}_{1}}-(-{{v}_{2}})|=80+30=110km\,h{{r}^{-1}}\]
    So time taken cross each other
    \[{{t}_{2}}=\frac{180}{110\times \frac{1000}{3600}}=\frac{18\times 36}{110}s\]
    Ration\[\frac{{{t}_{1}}}{{{t}_{2}}}=\frac{25}{\frac{18\times 36}{110}}=\frac{11}{5}\]


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