JEE Main & Advanced Physics Transmission of Heat JEE PYQ-Transmission Of Heat

  • question_answer
    Two kg of a monoatomic gas is at a pressure of \[4\times {{10}^{4}}N/{{m}^{2}}\]. The density of the gas is \[8\text{ }kg/{{m}^{3}}\]. What is the order of energy of the gas due to its thermal motion?   [JEE Main 10-Jan-2019 Evening]

    A)  \[{{10}^{4}}\] J         

    B)       \[{{10}^{3}}J\]

    C)  \[{{10}^{5}}\text{ }J\]           

    D)       \[{{10}^{6}}J\]

    Correct Answer: A

    Solution :

    [a] \[P=\frac{\rho RT}{M}\]
    \[4\times {{10}^{4}}=\frac{8}{4\times 1.6\times {{10}^{-27}}}~\,\times 8.314\,T\]
    \[E\,\,=\,\,\frac{3}{2}\,PV\,=\,\frac{3}{2}\times 4\times {{10}^{4}}\,\times \frac{2}{8.4}\,=\,1.5\times {{10}^{4}}\]


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