JEE Main & Advanced Physics Transmission of Heat JEE PYQ-Transmission Of Heat

  • question_answer
    A heat source at \[T={{10}^{3}}\] K is connected to another heat reservoir at \[T={{10}^{2}}\] K by a copper slab which is 1 m thick. Given that the thermal conductivity of copper is 0.1 \[W{{K}^{-}}^{1}{{m}^{-}}^{1}\], the energy flux through it in the steady state is – [JEE Main 10-Jan-2019 Morning]

    A)  200 \[W{{m}^{-}}^{2}\]                   

    B)  65 \[W{{m}^{-}}^{2}\]

    C)  120 \[W{{m}^{-}}^{2}\]       

    D)       90 \[W{{m}^{-}}^{2}\]

    Correct Answer: D

    Solution :

    [d] Heat current \[H\,\,=\,\,\frac{kA\Delta T}{L}\]
    Heat flux \[=\,\frac{H}{A}\,\,=\,\frac{k\,\Delta \,T}{L}\,=\,\frac{0.1(900)}{1}\]
    \[=\text{ }90\text{ }W{{m}^{-}}^{2}\]


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