question_answer

Wavelength of light used in an optical instrument are \[{{\lambda }_{1}}=4000\,\overset{0}{\mathop{A}}\,\] and \[{{\lambda }_{2}}=5000\,\overset{0}{\mathop{A}}\,\], then ratio of their respective resolving powers (corresponding to\[{{\lambda }_{1}}\]and\[{{\lambda }_{2}}\]) is                                            [AIEEE 2002]

A)  \[16:25\] 

B)                   \[9:1\]

C)  \[4:5\]              

D)       \[5:4\]

Correct Answer: D

Solution :

[d] Resolving power (RP) of an optical instrument is inversely proportional to  i.e., RP .