JEE Main & Advanced Physics Thermodynamical Processes JEE PYQ-Thermodynamical Processes

  • question_answer
    'n' moles of an ideal gas undergoes a process \[A\to B\]as shown in the figure. The maximum temperature of the gas during the process will be:                                                             [JEE MAIN - I 3-4-2016]

    A) \[\frac{9{{P}_{0}}{{V}_{0}}}{nR}\]    

    B)      \[\frac{9{{P}_{0}}{{V}_{0}}}{4nR}\]

    C) \[\frac{3{{P}_{0}}{{V}_{0}}}{2nR}\]  

    D)      \[\frac{9{{P}_{0}}{{V}_{0}}}{2nR}\]

    Correct Answer: B

    Solution :

    [b] T will be max where product of PV is max.
    equation of line
    (says)
     here PV product is max.
    Alternate
    Since initial and final temperature are equal hence maximum temperature is at middle of line. PV = nRT


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