JEE Main & Advanced Physics Thermodynamical Processes JEE PYQ-Thermodynamical Processes

  • question_answer
    The equation of state for a gas is given by PV = nRT + aV, where n is the number of moles and a is a positive constant. The initial temperature and pressure of one mole of the gas contained in a cylinder are \[{{T}_{o}}\]and \[{{P}_{o}}\]respectively. The work done by the gas when its temperature doubles isobarically will be:                            [JEE ONLINE 09-04-2014]

    A) \[\frac{{{P}_{o}}{{T}_{o}}R}{{{P}_{o}}-\alpha }\]     

    B)      \[\frac{{{P}_{o}}{{T}_{o}}R}{{{P}_{o}}+\alpha }\]

    C) \[{{P}_{o}}{{T}_{o}}R\ln 2\]   

    D)      \[{{P}_{o}}{{T}_{o}}R\]

    Correct Answer: A


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