JEE Main & Advanced Physics Simple Harmonic Motion JEE PYQ-Simple Harmonic Motion

  • question_answer
    A particle is executing simple harmonic motion (SHM) of amplitude A, along the x-axis, about\[x=0\]. When its potential Energy (PE) equals kinetic energy (KE), the position of the particle will be:      [JEE Main 09-Jan-2019 Evening]

    A)  \[\frac{A}{2\sqrt{2}}\]              

    B)       \[\frac{A}{\sqrt{2}}\]

    C)  \[\frac{A}{2}\]             

    D)       A

    Correct Answer: B

    Solution :

    [b] \[KE=PE\]
    \[\frac{1}{2}k({{A}^{2}}-{{x}^{2}})=\frac{1}{2}k{{x}^{2}}\]
    \[{{A}^{2}}\,=\,\,2{{x}^{2}}\]
    \[x=\frac{A}{\sqrt{2}}\]


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