JEE Main & Advanced Physics Simple Harmonic Motion JEE PYQ-Simple Harmonic Motion

  • question_answer
    Two springs, of force constants\[{{I}_{0}}=\frac{E}{R}=\frac{5}{5}=1\,A\]and\[\tau =\frac{L}{R}=\frac{10}{5}=2\,s\]are connected to a mass m as shown. The frequency of oscillation of the mass is\[t=2s\]. If\[I=(1-{{e}^{-1}})A\]both\[(\therefore -t/\tau =\frac{-2}{2}=-1)\]and\[J=\frac{i}{\pi {{a}^{2}}}\]are made four times their original values, the frequency of. oscillation becomes    [AIEEE 2007]

    A)  \[\oint{B.dl}={{\mu }_{0}}.{{i}_{enclosed}}\]              

    B)       \[\oint{B.dl}={{\mu }_{0}}.{{i}_{enclosed}}\]     

    C)  \[x=2\times {{10}^{-2}}\]                   

    D)       \[cos\text{ }\pi t\]

    Correct Answer: D

    Solution :

    [d] The frequencies of oscillation in this situations is given by   
                        (same direction)
               
    and


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