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JEE Main & Advanced Physics Rotational Motion JEE PYQ-Rotational Motion

  • question_answer
    An elevator in a building can carry a maximum of 10 persons, with the average mass of each person being 68 kg. The mass of the elevator itself is 920 kg and it moves with a constant speed of 3 m/s. The frictional force opposing the motion is 6000 N. If the elevator is moving up with its full capacity, the power delivered by the motor to the elevator \[(g=10\text{ }m/{{s}^{2}})\]must be at least                                     [JEE MAIN Held on 07-01-2020 Evening]

    A)   56300 W

    B)                    66000 W

    C)   48000 W        

    D)        62360 W

    Correct Answer: B

    Solution :

    [b] \[F=(10\text{ }m+M)g+f\] where, m = 68 kg, M = 920 kg, f = 6000 N \[\Rightarrow \,\,\,\,\,F=22000\text{ }N\] \[\Rightarrow \,\,\,\,\,P=FV=22000\times 3=66000\text{ }W\]


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