JEE Main & Advanced Physics Motion in a Straight Line / सरल रेखा में गति JEE PYQ - One Dimensional Motion

  • question_answer
    An object, moving with a speed of \[6.25\,m/s\], is decelerated at a rate given by \[\frac{d\upsilon }{dt}=-2.5\sqrt{v}\] where v is the instantaneous speed. The time taken by the object, to come to rest, would be [AIEEE 2011]

    A)             8 s

    B) 1 s

    C)             2 s

    D) 4 s

    Correct Answer: C

    Solution :

    [c]  \[\int\limits_{v}^{0}{\frac{d\upsilon }{\sqrt{\upsilon }}=-\int\limits_{0}^{t}{2.5\,dt}}\]
    \[2\sqrt{\upsilon }=2.5\,t\]
    \[2\sqrt{6.25}=2.5\,t\]
    \[t=2\,s\]


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