JEE Main & Advanced Physics NLM, Friction, Circular Motion JEE PYQ - NLM Friction Circular Motion

Two cars of masses \[{{m}_{1}}\] and \[{{m}_{2}}\] are moving in circles of radii \[{{r}_{1}}\] and \[{{r}_{2}}\], respectively. Their speeds are such that they make complete circles in the same time t. The ratio of their centripetal acceleration is: [AIEEE 2012]

A) \[{{m}_{1}}{{r}_{1}}:{{m}_{2}}{{r}_{2}}\]

B) \[{{m}_{1}}:{{m}_{2}}\]

C) \[{{r}_{1}}:{{r}_{2}}\]

D) \[1:1\]

Correct Answer: C

Solution :

[c] They have same \[\omega \].

centripetal acceleration \[={{\omega }^{2}}r\]

\[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{{{\omega }^{2}}{{r}_{1}}}{{{\omega }^{2}}{{r}_{2}}}=\frac{{{r}_{1}}}{{{r}_{2}}}\]