A) \[M{{T}^{-1}}{{C}^{-1}}\]
B) \[M{{T}^{-2}}{{C}^{-1}}\]
C) \[ML{{T}^{-1}}{{C}^{-1}}\]
D) \[M{{T}^{2}}{{C}^{-2}}\]
Correct Answer: A
Solution :
| [a] Use \[F=iBl\] |
| \[\left[ ML{{T}^{-2}} \right]=\left[ \frac{C}{T} \right]\left[ B \right]\left[ L \right]\] \[\therefore \,\,\left[ B \right]=\left[ M{{T}^{-1}}{{C}^{-1}} \right]\] |
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