| For the four sets of three measured physical quantities as given below. Which of the following options is correct? |
| (i) \[{{A}_{1}}=24.36,\,\,\,\,{{B}_{1}}=0.0724,\,\,\,{{C}_{1}}=256.2\] |
| (ii) \[{{A}_{2}}=24.44,\,\,\,\,{{B}_{2}}=16.082,\,\,\,{{C}_{2}}=240.2\] |
| (iii) \[{{A}_{3}}=25.2,\,\,\,\,{{B}_{3}}=19.2812,\,\,\,{{C}_{3}}=236.183\] |
| (iv) \[{{A}_{4}}=25,\,\,\,\,{{B}_{4}}=236.191,\,\,\,{{C}_{4}}=19.5\] [JEE MAIN Held on 09-01-2020 Evening] |
A) \[{{A}_{1}}+{{B}_{1}}+{{C}_{1}}={{A}_{2}}+{{B}_{2}}+{{C}_{2}}={{A}_{3}}+{{B}_{3}}+{{C}_{3}}=\]\[{{A}_{4}}+{{B}_{4}}+{{C}_{4}}\]
B) \[{{A}_{1}}+{{B}_{1}}+{{C}_{1}}<{{A}_{3}}+{{B}_{3}}+{{C}_{3}}<{{A}_{2}}+{{B}_{2}}+{{C}_{2}}<\]\[{{A}_{4}}+{{B}_{4}}+{{C}_{4}}\]
C) \[{{A}_{4}}+{{B}_{4}}+{{C}_{4}}<{{A}_{1}}+{{B}_{1}}+{{C}_{1}}={{A}_{2}}+{{B}_{2}}+{{C}_{2}}=\]\[{{A}_{3}}+{{B}_{3}}+{{C}_{3}}\]
D) None of these
Correct Answer: D
Solution :
| (Bonus) \[{{A}_{1}}+{{B}_{1}}+{{C}_{1}}=280.6\] |
| \[{{A}_{2}}+{{B}_{2}}+{{C}_{2}}=280.7\] |
| \[{{A}_{3}}+{{B}_{3}}+{{C}_{3}}=280.7\] |
| \[{{A}_{4}}+{{B}_{4}}+{{C}_{4}}=281\] |
| None of the option matches. |
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