JEE Main & Advanced Physics Mathematical Tools, Units & Dimensions JEE PYQ - Mathematical Tools Units and Dimensions

  • question_answer
    Expression for time in terms of G (universal gravitational constant), h (Planck constant) and c (speed of light) is proportional to:                                        [JEE Main 09-Jan-2019 Evening]

    A)       \[\sqrt{\frac{Gh}{{{c}^{5}}}}\]

    B) \[\sqrt{\frac{h{{c}^{5}}}{G}}\]

    C) \[\sqrt{\frac{Gh}{{{c}^{3}}}}\]

    D) \[\sqrt{\frac{{{c}^{3}}}{Gh}}\]

    Correct Answer: A

    Solution :

    [a] \[T\,\,=\,\,k{{G}^{a}}{{h}^{b}}{{c}^{c}}\]
    \[[T]={{[{{M}^{-1}}\,{{L}^{3}}{{T}^{-2}}]}^{a}}\,\,{{[M{{L}^{2}}{{T}^{-1}}]}^{b}}\,{{[L{{T}^{-1}}]}^{c}}\]
    \[=\,\,{{M}^{-a+b}}\,L{{\,}^{3a+2b+c}}\,{{T}^{-2a-b-c}}\]
    \[~-a+b=0\]
    \[\Rightarrow \,\,\,a=b~~~~~~~~...\left( 1 \right)\]
    \[3a+2b+c=0~~~~~~...\left( 2 \right)\]
    \[-2a-b-c=1~~~~~~~~~~~...\left( 3 \right)\]
    \[a+b=1\]
    \[a=b\,\text{=}\,\frac{1}{2}\]
    \[C=-2\,\,\times \,\,\frac{1}{2}-\frac{1}{2}-1=-\frac{5}{2}\]
    \[T\,\propto \,\frac{{{G}^{\frac{1}{2}}}{{h}^{\frac{1}{2}}}}{{{C}^{\frac{5}{2}}}}\,=\,\sqrt{\frac{Gh}{{{C}^{5}}}}\]
    Option [a]


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