JEE Main & Advanced Physics Mathematical Tools, Units & Dimensions JEE PYQ - Mathematical Tools Units and Dimensions

  • question_answer
    The relative error in the determination of the surface area of a sphere is\[\alpha \]. Then the relative error in the determination of its volume is : [JEE Online 15-04-2018]

    A)       \[\frac{2}{3}\alpha \]     

    B) \[\frac{5}{2}\alpha \]

    C) \[\frac{3}{2}\alpha \]     

    D) \[\alpha \]

    Correct Answer: C

    Solution :

    [c] \[S=\]\[4\pi {{R}^{2}}\]
    In \[S=In(4\pi )+In({{R}^{2}})\]
    In \[S=2\] In \[R\]
    \[\frac{\Delta S}{S}=2\frac{\Delta R}{R}=\alpha \]
    \[\frac{\Delta R}{R}=\frac{\alpha }{2}..............(1)\]
    \[V=\frac{4}{3}\pi {{R}^{3}}\]
    In \[V=In(\frac{4}{3}\pi )+In\,\,{{R}^{3}}\]
    In \[V=3\,\,In\,\,R\]
    \[\frac{\Delta V}{V}=3\frac{\Delta R}{R}\]
    \[\frac{\Delta V}{V}=3(\frac{\alpha }{2})\]m


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