A) A screw gauge having 100 divisions in the circular scale and pitch as 1 mm.
B) A screw gauge having 50 divisions in the circular scale and pitch as 1 mm.
C) A meter scale.
D) A vernier calliper where the 10 divisions in vernier scale matches with 9 division in main scale & main scale has 10 divisions in 1 cm
Correct Answer: D
Solution :
| [d] Least count = 0.01 cm i.e. 0.1 mm for vernier calliper of 10 v.s.d. = 9 M.s. d. |
| 1 v.s.d. = 0.9 M.s.d. |
| L.C. = 1 M.s.d |
| = (0.1) M.s.d. |
| 1 v.s.d. = 0.1 cm |
| \[\Rightarrow \] L.c = 0.01 cm |
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