A) 1.83
B) 4.67
C) 2.3
D) None of these
Correct Answer: D
Solution :
| [d] (1.09) Bonus |
| \[\lambda =\frac{1}{\sqrt{2}\pi {{d}^{2}}n}\] |
| Mean free time, \[\tau =\frac{\lambda }{v}\] |
| \[\tau \propto \frac{\sqrt{M}}{{{d}^{2}}}\] |
| \[\frac{{{\tau }_{1}}}{{{\tau }_{2}}}=\frac{\sqrt{{{M}_{1}}}}{{{d}_{1}}^{2}}\times \frac{{{d}_{2}}^{2}}{\sqrt{{{M}_{2}}}}\] |
| \[=\sqrt{\frac{40}{140}}\times {{\left( \frac{0.1}{0.07} \right)}^{2}}=1.09\] |
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