A) \[9\times {{10}^{6}}J\]
B) \[3\times {{10}^{2}}J\]
C) \[6\times {{10}^{4}}J\]
D) \[{{10}^{8}}J\]
Correct Answer: A
Solution :
| [a] We know that \[PV=\frac{2}{3}E\] |
| \[E=\frac{3PV}{2}=3\times \frac{3\times {{10}^{6}}}{2}\times 2=9\times {{10}^{6}}J\] |
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