question_answer

The energy required to take a satellite to a height ‘h’ above Earth surface (radius of Earth \[=6.4\times {{10}^{3}}km\]) is \[{{E}_{1}}\] and kinetic energy required for the satellite to be in a circular orbit at this height is \[{{E}_{2}}\]. The value of h for which \[{{E}_{1}}\] and \[{{E}_{2}}\] are equal, is:                            [JEE Main 09-Jan-2019 Evening]

A)  \[3.2\times {{10}^{3}}\text{ }km\]      

B)       \[1.6\times {{10}^{3}}km\] C)  \[1.28\times {{10}^{4}}km\] D)       \[6.4\times {{10}^{3}}km\] Correct Answer: A Solution : [a]