question_answer

Take the mean distance of the moon and the sun from the earth to be \[0.4\times {{10}^{6}}km\]and \[150\times {{10}^{6}}km\] respectively. Their masses are \[8\times {{10}^{22}}kg\]and \[2\times {{10}^{30}}kg\] respectively. The radius of the earth is\[6400km\]. Let \[\Delta {{F}_{1}}\] be the difference in the forces exerted by the moon at the nearest and farthest points on the earth and \[\Delta {{F}_{2}}\] be the difference in the force exerted by the sun at the nearest and farthest points on the earth. Then, the number closest to \[\frac{\Delta {{F}_{1}}}{\Delta {{F}_{2}}}\] is: [JEE Online 15-04-2018]

A)  2                    

B)       6

C)  \[{{10}^{-2}}\]                      

D)       0.6 Correct Answer: C Solution : [c]

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