JEE Main & Advanced Physics Elasticity JEE PYQ-Elasticity

  • question_answer
    If the ratio of lengths, radii and Young’ module of steel and brass wires in the figure are a, b and c respectively, then the corresponding ration of increase in lengths is:                     
    [JEE ONLINE 09-04-2013]

    A)       \[\frac{3c}{2a{{b}^{2}}}\]                  

    B) \[\frac{2{{a}^{2}}c}{b}\]

    C) \[\frac{3a}{2{{b}^{2}}c}\]      

    D) \[\frac{2ac}{{{b}^{2}}}\]

    Correct Answer: C

    Solution :

    [c] For steel wire
    As change in length \[(\Delta {{l}_{1}})=\frac{3Mg{{l}_{1}}}{r_{1}^{2}\pi {{y}_{1}}}\]             ...(i)
    and for beam wire,
    Change in length  \[(\Delta {{l}_{2}})=\frac{2Mg\,{{l}_{2}}}{\pi r_{2}^{2}{{y}_{2}}}\]             ...(ii)
    Dividing Eq. (i) by (ii), we get, r
    Corresponding ratio of increase in their lengths \[=\frac{3a}{2{{b}^{2}}c}\]


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