A) \[{{\text{O}}^{2-}},{{F}^{-}},N{{a}^{+}},M{{g}^{2+}}\]
B) \[{{O}^{-}},{{F}^{-}},Na,M{{g}^{+}}\]
C) \[{{O}^{2-}},{{F}^{-}},Na,M{{g}^{2+}}\]
D) \[{{O}^{-}},{{F}^{-}},N{{a}^{+}},M{{g}^{2+}}\]
Correct Answer: A
Solution :
\[\begin{align} & \text{ions}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{{O}^{-2}}\,\,{{F}^{-}}\,\,\,N{{a}^{+}}\,\,\,M{{g}^{+2}} \\ & \text{Atomic}\,\text{number}\,=\,\,\,8\,\,\,\,\,\,\,\,9\,\,\,\,\,\,\,11\,\,\,\,\,\,\,\,12 \\ & \text{No}\text{.}\,\text{of}\,{{e}^{-}}=\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,10\,\,\,\,\,10\,\,\,\,\,\,10\,\,\,\,\,\,\,10 \\ \end{align}\] therefore\[{{O}^{2-}},{{F}^{-}},N{{a}^{+}},M{{g}^{+2}}\]are isoelectronic
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