A) Isochoric work
B) Isobaric work
C) Adiabatic work
D) Isothermal work
Correct Answer: C
Solution :
From 1st law \[\Delta U=q+w\] For adiabatic process: q = 0 \[\therefore \] \[\Delta U=w\] \[\therefore \]Work involve in adiabatic process is at the expense of change in internal energy of the system.
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