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JEE Main & Advanced JEE Main Solved Paper-2017

  • question_answer
    An observer is moving with half the speed of light towards a stationary microwave source emitting waves at frequency 10 GHz. What is the frequency of the microwave measured by the observer?   (speed of light\[=3\times {{10}^{8}}\,m{{s}^{-1}}\])   JEE Main Solved Paper-2017

    A)  17.3 GHz                            

    B)  15.3 GHz

    C)  10.1 GHz                            

    D)  12.1 GHz

    Correct Answer: A

    Solution :

     Doppler effect in light (speed of observer is not very small compare to speed of light)                 \[{{f}^{1}}=\sqrt{\frac{1+V/C}{1-V/C}}{{f}_{source}}=\sqrt{\frac{1+1/2}{1-1/2}}(10\,GHz)\] \[=17.3\,GHz\]


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