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JEE Main & Advanced JEE Main Solved Paper-2017

  • question_answer
    A magnetic needle of magnetic moment \[6.7\times {{10}^{-2}}\,A{{m}^{2}}\]and moment of inertia \[7.5\times {{10}^{-6}}\,kg\,{{m}^{2}}\]is performing simple harmonic oscillations in a magnetic field of 0.01 T. Time taken for 10 complete oscillations is:    JEE Main Solved Paper-2017

    A)  6.98 s                   

    B)  8.76 s

    C)  6.65 s                   

    D)  8.89 s

    Correct Answer: C

    Solution :

     \[T=2\pi \sqrt{\frac{I}{MB}}\]                 \[I=7.5\times {{10}^{-6}}kg-{{m}^{2}}\] \[M=6.7\times {{10}^{-2}}A{{m}^{2}}\] By substituting value in the formula \[T=.665\,\sec \] for 10 oscillation, time taken will be Time = 10 T = 6.65 sec Answer option 3


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