A) 0.065 H
B) 80 H
C) 0.08 H
D) 0.044 H
Correct Answer: A
Solution :
I = 10A V = 80v \[R=8\Omega \] \[10=\frac{220}{\sqrt{{{8}^{2}}+X_{L}^{2}}}\] \[{{X}_{L}}^{2}+64=484\] \[{{X}_{L}}=\sqrt{420}\] \[2\pi \times 50L=\sqrt{420}\] \[L=\frac{\sqrt{420}}{100\pi }\] \[\]
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