JEE Main & Advanced JEE Main Solved Paper-2015

  • question_answer
    5 Assuming human pupil to have a radius of 0.25 cm and a comfortable viewing distance of 25 cm, the minimum separation between two objects that human eye can resolve at 500 nm wavelength is [JEE Main Solved Paper-2015 ]

    A) \[100\mu m\]                   

    B) \[300\mu m\]

    C) \[1\mu m\]                        

    D) \[30\mu m\]

    Correct Answer: D

    Solution :

                    \[2\theta =\frac{1.22\lambda }{d}\] \[2\theta =1.22\times 5\times {{10}^{-6}}\] \[d=R2\theta =\frac{1}{4}\times 1.22\times 5\times {{10}^{-6}}\] \[\cong 30\mu m\]


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