A) forward direction because \[Q<{{K}_{C}}\]
B) reverse direction because \[Q<{{K}_{C}}\]
C) forward direction because \[Q>{{K}_{C}}\]
D) reverse direction beacuse \[Q>{{K}_{C}}\]
Correct Answer: D
Solution :
\[Q=\frac{\left[ B \right]\left[ C \right]}{{{\left[ A \right]}^{2}}}=\frac{2\times \frac{1}{2}}{\frac{1}{2}\times \frac{1}{2}}=4\] \[\Delta {{G}^{0}}=-2.303RT\log {{K}_{eq}}\] \[2494.2=-2.303\times 8.314\times 300\times \log K\] \[-\log K=0.434\] \[\log \frac{1}{K}=0.434\] \[\frac{1}{K}=2.7\] \[K=\frac{1}{2.7}=0.37\] \[\therefore \]\[Q>K\] \[\therefore \] Backward reaction favoured i.e. reverse direction
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